[alexkill]

посмотрите, что "сотворил" я, направьте на путь истинный, ибо как вставить картинку во фрейм, я не понял немного

<script> 
function check(newer)
{
	params  = "#uploader"
	request = new ajaxRequest()
	request.open("POST", "upload.php", true)
	request.setRequestHeader("Content-type", "application/x-www-form-urlencoded")
	request.setRequestHeader("Content-length", params.length)
	request.setRequestHeader("Connection", "close")
	
	request.onreadystatechange = function()
	{
		if (this.readyState == 4)
		{
			if (this.status == 200)
			{
				if (this.responseText != null)
				{
					document.getElementById('uploader').style.display='inherit';
					<?php 
						if (isset($_FILES['image']['name']))
						{
 							$saveto = "lmt_image/ava.jpg";
							$dir = "lmt_image";
	
							if (!file_exists($dir)) 
							{
								$old = umask(0);
								mkdir($dir,0777);
								umask($old); 
							}
						move_uploaded_file($_FILES['image']['tmp_name'], $saveto);
						}
					?>
				}
				else alert("Ajax error: No data received")
			}
			else alert( "Ajax error: " + this.statusText)
		}
	}
	request.send(params)
}

function ajaxRequest()
{
	try
	{
		var request = new XMLHttpRequest()
	}
	catch(e1)
	{
		try
		{
			request = new ActiveXObject("Msxml2.XMLHTTP")
		}
		catch(e2)
		{
			try
			{
				request = new ActiveXObject("Microsoft.XMLHTTP")
			}
			catch(e3)
			{
				request = false
			}
		}
	}
	return request
}
</script>

<form action="#uploader" name="photo" enctype="multipart/form-data" onsubmit="check(this)" method="post">
  <input type="file" name="image" size="30" />
  <input type="submit" name="upload" value="Upload" />
</form>

<iframe name="uploader" id="uploader" style="display: none;"></iframe>