разбирайся
http://james.padolsey.com/javascript...s-with-jquery/
<script src="http://code.jquery.com/jquery-1.8.3.min.js"></script>
<div id='box'>
<div id='d'><a href="1.php">Вася</a></div>
<div id='d'><a href="2.php">Аня</a></div>
<div id='d'><a href="3.php">Вова</a></div>
<div id='d'><a href="4.php">Боря</a></div>
</div>
<button>click</button>
<script>
/**
* jQuery.fn.sortElements
* --------------
* @param Function comparator:
* Exactly the same behaviour as [1,2,3].sort(comparator)
*
* @param Function getSortable
* A function that should return the element that is
* to be sorted. The comparator will run on the
* current collection, but you may want the actual
* resulting sort to occur on a parent or another
* associated element.
*
* E.g. $('td').sortElements(comparator, function(){
* return this.parentNode;
* })
*
* The <td>'s parent (<tr>) will be sorted instead
* of the <td> itself.
*/
jQuery.fn.sortElements = (function(){
var sort = [].sort;
return function(comparator, getSortable) {
getSortable = getSortable || function(){return this;};
var placements = this.map(function(){
var sortElement = getSortable.call(this),
parentNode = sortElement.parentNode,
// Since the element itself will change position, we have
// to have some way of storing its original position in
// the DOM. The easiest way is to have a 'flag' node:
nextSibling = parentNode.insertBefore(
document.createTextNode(''),
sortElement.nextSibling
);
return function() {
if (parentNode === this) {
throw new Error(
"You can't sort elements if any one is a descendant of another."
);
}
// Insert before flag:
parentNode.insertBefore(this, nextSibling);
// Remove flag:
parentNode.removeChild(nextSibling);
};
});
return sort.call(this, comparator).each(function(i){
placements[i].call(getSortable.call(this));
});
};
})();
$("button").on("click", function () {
$('#box div').sortElements(function(a, b){
return $(a).text() > $(b).text() ? 1 : -1;
});
});
</script>