[zaza41rus]

как в это

var dataString = 'name='+ name + '&email=' + email + '&phone=' + phone;

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добавить это:

function emailCheckout(form){
    var me=simpleCart;counter=1;
    form.appendChild(me.createHiddenElement("currency",me.currency));

    for(var current in me.items){
    var item=me.items[current];

    form.appendChild(me.createHiddenElement("name_"+counter,item.name));
    form.appendChild(me.createHiddenElement("quantity_"+counter,item.qty));
    form.appendChild(me.createHiddenElement("price_"+counter,item.price));


    var descriptionString="";
    for(var field in item){if(typeof(item[field])!="function"&&field!="id"&&field!="qty"&&field!="price"){

    descriptionString=descriptionString+", "+field+": "+item[field]}}descriptionString=descriptionString.substring(1);
    form.appendChild(me.createHiddenElement("item_description_"+counter,descriptionString));
    counter++}
    }

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чтоб сработало это:

$.ajax({
      type: "POST",
      url: "checkout.php",
      data: dataString,

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И по завершении произошла очистка форм