[nerv_]

могу дать это

$.postForm = function(uri, form, onSuccess) {
    var formElement = $(form).get(0);
    var formData = new FormData(formElement);
    var onAjaxSuccess = onSuccess || $.noop;
    return $.ajax({
        url: uri,
        type: 'POST',
        data: formData,
        cache: false,
        dataType: 'json',
        processData: false,
        contentType: false,
        success: onAjaxSuccess
    });
};

$('#test-form').submit(function(event) {
    event.preventDefault();

    $.postForm('/demo/echo.php', this).success(function(data) {
        console.log(data);
    });
});

дальше сам =)