[leon2009sp]

можно еще вопросик, почему не выводит на второй раз результат,
и можно ли передать результат в {$s_city} строка 3,4

<script>
        function loadXMLDoc(filename) {
            if (window.ActiveXObject) {
                xhttp = new ActiveXObject("Msxml2.XMLHTTP");
            }
            else {
                xhttp = new XMLHttpRequest();
            }
            xhttp.open("GET", filename, false);
            try { xhttp.responseType = "msxml-document" } catch (err) { } // Helping IE11
            xhttp.send(null);
            return xhttp.responseXML;
        }
        document.addEventListener('DOMContentLoaded', function () {
            var xml = loadXMLDoc("xml/city_reg.xml"),
                selCity = document.querySelector('#city'),			
				selStation = document.getElementById('ob');				
            [].forEach.call(xml.querySelectorAll('city'), function (el) {
                selCity.add(new Option(el.getAttribute('name'), el.getAttribute('name')))
		})
            selCity.addEventListener('change', function () {
                [].forEach.call(xml.querySelectorAll('city[name=' + this.value + '] > ob'), function (el) {
					selStation.innerHTML = el.textContent;
                })
            })
        })
    </script>
    <select id=city><option selected>1111111</option></select>   
	<a href=ob id=ob name=links2>111</a>
	<a href=ob id=ob name=links2>111</a>
<?php
echo "
<table align=center border=0 cellpadding=0 cellspacing=0 width=100% class=inf4>
<tr>
<td align=center width=15% title=num1><ul class=tops>";
foreach($xml_db->cat_a as $cat_a)
{
echo "<ol class=link1><font color=#ADADAB>{$cat_a['category']}</font></ol>";
foreach($cat_a->marka as $marka)
{
echo "<li align=left><a href=db/auto/{$s_city}/{$marka['link']} class=link2>{$marka['name']}</a></li>";	
}
}
?>