Сообщение от DzonyB
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Если нужны мои потуги
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аналогично
что - то из разряда ... слеплено из ... )))
<script>
function permute(arr) {
let l = arr.length,
used = Array(l),
data = Array(l);
return function* backtracking(pos) {
if (pos == l) yield data.slice();
else
for (let i = 0; i < l; ++i)
if (!used[i]) {
used[i] = true;
data[pos] = arr[i];
yield* backtracking(pos + 1);
used[i] = false;
}
}(0);
}
function sumArray(arr) {
return arr.reduce((a, b) => a + b, 0)
}
function permutDevide(arr, n) {
arr.sort((a, b) => a - b);
const gen = permute(arr);
let current = gen.next();
let max = [],
k = 0,
sum = sumArray(arr);
while (!current.done) {
let temp = [],
num = 0,
d = 0,
s = sum;
const res = [temp];
for (const elem of current.value) {
if(num + elem > n && s != elem || (elem > n)) {
if(num == n) d++;
temp = [elem];
res.push(temp);
num = elem;
}
else {
temp.push(elem);
num += elem;
}
s -= elem;
}
if(num == n) d++;
if (!temp.length) res.pop();
if (d >= sum / n - 1.5) return res;
if (!max.length) max = res;
if (d > k) {
max = res;
k = d
};
current = gen.next();
}
return max
}
const test = [
[1, 2, 4, 7, 1, 6, 2, 8], [5, 2, 5, 1, 5, 4, 6, 3], [100, 8, 7, 3, 1, 45, 20, 6, 4], [2, 2, 3, 9, 5, 6, 1], [3, 3, 3, 3, 3, 3], [3, 7, 3, 3, 3, 3]
];
for (const arr of test) document.write(`${JSON.stringify(arr)} => ${JSON.stringify(permutDevide(arr, 10))}<br>`)
</script>