Получить разницу двух дат

[NovichokJS]

Мне нужно получить разницу в таком формате:

9d 21h 103m 80s

Написал код:

const getDiff = (startDate, endDate) => {
  let date1 = new Date(startDate);
  let date2 = new Date(endDate);

  let days = Math.round(Math.abs((date1 - date2) / (1000 * 60 * 60 * 24)));
  let hours = Math.round(Math.abs((date1 - date2) / (1000 * 60 * 60)));
  let minutes = Math.round(Math.abs((date1 - date2) / (1000 * 60)));
  let seconds = Math.round(Math.abs((date1 - date2) / 1000));

  return `${days}d ${hours}h ${minutes}m ${seconds}s`;
};
console.log(getDiff(new Date(2022, 11, 18, 3, 25, 0), new Date(2022, 11, 9, 1, 2, 0)));
console.log(getDiff(new Date(2022, 11, 9, 1, 2, 0), new Date(2022, 11, 18, 3, 25, 0)));

Получается что некорректно..

[рони]

NovichokJS,

const getDiff = (startDate, endDate) => {
  let date1 = new Date(startDate);
  let date2 = new Date(endDate);
  let difference = Math.abs(date1 - date2);
  let days = Math.round(difference / (1000 * 60 * 60 * 24));
  difference -= days * (1000 * 60 * 60 * 24)
  let hours = Math.round(difference / (1000 * 60 * 60));
  difference -= hours * (1000 * 60 * 60)
  let minutes = Math.round(difference /  (1000 * 60));
  difference -= minutes * (1000 * 60)
  let seconds = difference;

  return `${days}d ${hours}h ${minutes}m ${seconds}s`;
};
console.log(getDiff(new Date(2022, 11, 18, 3, 25, 0), new Date(2022, 11, 9, 1, 2, 0)));
console.log(getDiff(new Date(2022, 11, 9, 1, 2, 0), new Date(2022, 11, 18, 3, 25, 0)));

[NovichokJS]

const getDiff = (startDate, endDate) => {
  let date1 = new Date(startDate);
  let date2 = new Date(endDate);
  let difference = Math.abs(date1 - date2);
  let days = Math.round(difference / (1000 * 60 * 60 * 24));
  difference -= days * (1000 * 60 * 60 * 24)
  let hours = Math.round(difference / (1000 * 60 * 60));
  difference -= hours * (1000 * 60 * 60)
  let minutes = Math.round(difference /  (1000 * 60));
  difference -= minutes * (1000 * 60)
  let seconds = difference;

  return `${days}d ${hours}h ${minutes}m ${seconds}s`;
};
console.log(getDiff(new Date(2022, 11, 18, 3, 25, 0), new Date(2022, 11, 9, 1, 2, 0)));
console.log(getDiff(new Date(2022, 11, 9, 1, 2, 0), new Date(2022, 11, 18, 3, 25, 0)));

Тесты возвращают результат:

• Функция getDiff должна вернуть разницу двух дат
• Функция getDiff должна вернуть разницу двух дат, когда первая меньше второй

что-то не то((

[рони]

NovichokJS,
что не так?

[NovichokJS]

NovichokJS,
что не так?

let seconds = difference;

разве не надо тут делить на 1000 ?

[NovichokJS]

а нельзя решить с помощью методов getHours() и т.п? вместо того чтобы употреблять вот это hours * (1000 * 60 * 60) ?

[рони]

разве не надо тут делить на 1000 ?

ок.

const getDiff = (startDate, endDate) => {
  let date1 = new Date(startDate);
  let date2 = new Date(endDate);
  let difference = Math.abs(date1 - date2);
  let days = Math.trunc(difference / (1000 * 60 * 60 * 24));
  difference -= days * (1000 * 60 * 60 * 24)
  let hours = Math.trunc(difference / (1000 * 60 * 60));
  difference -= hours * (1000 * 60 * 60)
  let minutes = Math.trunc(difference /  (1000 * 60));
  difference -= minutes * (1000 * 60)
  let seconds = difference/1000;

  return `${days}d ${hours}h ${minutes}m ${seconds}s`;
};
console.log(getDiff(new Date(2022, 11, 18, 3, 25, 0), new Date(2022, 11, 9, 1, 2, 0)));
console.log(getDiff(new Date(2022, 11, 9, 1, 2, 0), new Date(2022, 11, 18, 3, 25, 0)));

[NovichokJS]

хух, проблема была в том что тут let seconds = difference/1000; был пропущен Math.trunc

[NovichokJS]

Рони, спасибо!

[rgl]

Альтертанивный вариант (извиняюсь что без новомодных let и =>)

function getDiff(startDate, endDate) {
//  var date1 = new Date(startDate);
//  var date2 = new Date(endDate);
//  var diff = Math.abs(date2-date1);
  var diff = Math.abs(new Date(endDate) - new Date(startDate));

  diff = (diff-(diff%1000))/1000;
  var seconds = diff % 60;
  diff = (diff-seconds)/60;
  var minutes = diff % 60;
  diff = (diff-minutes)/60;
  var hours = diff % 24;
  var days = (diff-hours)/24;
  return days+"d "+hours+"h "+minutes+"m "+seconds+"s";
}