<!DOCTYPE html>
<html>
<head>
<title>Untitled</title>
<meta charset="utf-8">
<style type="text/css">
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
$(function() {
function b() {
var d = c.slice(a, a + 10).reverse().join("<br>");
$("#slider").html(d);
a + 10 < c.length && (a++, window.setTimeout(b, 1E3))
}
var c = ['Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin','Valera Kunin']
var c = $.map(Array(50), function(a, b) {
return b
}),
a = 0;
b()
});
</script>
</head>
<body>
<div id="slider"></div>
</body>
</html>
сделал так, и не работает