Здравствуйте буду признателен за подсказку есть скрипт формы отправки ajax jquery
$(document).ready(function() {
//if submit button is clicked
$('#form4').submit(function () {
//Get the data from all the fields
var name4 = $('input[name=name4]');
var tel4 = $('input[name=tel4]');
var email4 = $('input[name=email4]');
//Simple validation to make sure user entered something
//If error found, add hightlight class to the text field
if (name4.val()=='') {
name4.addClass('hightlight');
return false;
} else name4.removeClass('hightlight');
if (tel4.val()=='') {
tel4.addClass('hightlight');
return false;
} else tel4.removeClass('hightlight');
if (email4.val()=='') {
email4.addClass('hightlight');
return false;
} else email4.removeClass('hightlight');
//organize the data properly
var data = 'name4=' + name4.val() + '&tel4=' +
tel4.val()+ '&email4=' + email4.val();
//disabled all the text fields
//show the loading sign
$('.loading4').show();
//start the ajax
$.ajax({
//this is the php file that processes the data and send mail
url: "process4.php",
//GET method is used
type: "GET",
//pass the data
data: data,
//Do not cache the page
cache: false,
//success
success: function (html) {
//if process.php returned 1/true (send mail success)
if (html==1) {
//hide the form
//show the success message
$('.loading4').fadeOut('slow');
$('.done4').fadeIn('slow');
$('form').fadeOut('slow');
$('form').fadeIn('slow');
//if process.php returned 0/false (send mail failed)
} else alert('Sorry, unexpected error. Please try again later.');
}
});
//cancel the submit button default behaviours
return false;
});
});
как сбросить форму?
jQuery('form')[0].reset();
про бывал
$('form')[0].reset.fadeIn('slow');
не вышло
выходит так
$('form').fadeOut('slow');//исчезает
$('form').fadeIn('slow');//появляется но форма не сброшена
